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Find the solubility of MnS in neutral water in gm/l .Ksp of MnS = 2.6 x 10-14

Find the solubility of MnS in neutral water in gm/l ? Ksp of MnS = 2.6 x 10-14.

Solution –

MnS ——-> Mn2+  + S2-

solubility  of MnS = S mole / litre

[Mn2+ ] = S mole / litre

[S2- ] = S mole / litre

It is 1 : 1 type  salt .so,

Ksp = S2

2.6 x 10-14 = S2

S = √ 2.6 x 10-14

S = 1.612 x 10-7 mole / litre

S in gm /litre = S ( mole/litre )x mol.wt.

mol.wt of MnS = 55 + 32 = 87

S in gm /litre = 1.612 x 10-7 x 87 =140.24 x 10-7

S = 1.40 x 10-5 gm /litre Ans.

 

 

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