Find the solubility of MnS in neutral water in gm/l .Ksp of MnS = 2.6 x 10-14

Find the solubility of MnS in neutral water in gm/l ? Ksp of MnS = 2.6 x 10^-14.

Solution –

MnS ——-> Mn²⁺  + S^2-

solubility  of MnS = S mole / litre

[Mn²⁺ ] = S mole / litre

[S^2- ] = S mole / litre

It is 1 : 1 type  salt .so,

Ksp = S²

2.6 x 10^-14 = S²

S = √ 2.6 x 10^-14

S = 1.612 x 10^-7 mole / litre

S in gm /litre = S ( mole/litre )x mol.wt.

mol.wt of MnS = 55 + 32 = 87

S in gm /litre = 1.612 x 10^-7 x 87 =140.24 x 10^-7

S = 1.40 x 10^-5 gm /litre Ans.